20-5-3(2x+4)+3(2^4)=20

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Solution for 20-5-3(2x+4)+3(2^4)=20 equation: 



20-5-3(2x+4)+3(2^4)=20

We move all terms to the left:

20-5-3(2x+4)+3(2^4)-(20)=0

determiningTheFunctionDomain
-3(2x+4)+20-5-20+32^4=0

We add all the numbers together, and all the variables

-3(2x+4)+1048571=0

We multiply parentheses

-6x-12+1048571=0

We add all the numbers together, and all the variables

-6x+1048559=0

We move all terms containing x to the left, all other terms to the right

-6x=-1048559

x=-1048559/-6

x=174759+5/6

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